Mar 12, 2017 · √6x − 5+10 −10 = 3 −10 ⇒ √6x −5 = −7 square both sides (√6x − 5)2 = (− 7)2 ⇒ 6x − 5 = 49 add 5 to both sides. 6x−5 +5 = 49+ 5 ⇒ 6x = 54 divide both sides by 6 6x 6 = 54 6 ⇒ …

Nov 19, 2016 · Explanation: After play with some of the pairs to combine #6, 24 and 30# #6x^2 - 24x - 30 = 0# can be factored to:

(x+6)/ (x-6) >"factorise numerator/denominator" • x^2+12x+36 "'split '12x into 6x + 6x" rArrx^2+6x+6x+36 "factor each 'pair' by taking out a "color (blue)"common ...

f (x) has zeros +-sqrt (5) and -2 Given: f (x) = 3x^3+6x^2-15x-30 Note that all of the terms are divisible by 3. In addition, the ratio of the first and second terms is the same as that of the third …

Jan 31, 2017 · 36x^2-25=(6x+5)(6x-5) Using the difference of squares formula a^2-b^2 = (a+b)(a-b), we have 36x^2-25 = 6^2x^2-5^2 =(6x)^2-5^2 =(6x+5)(6x-5)

Jan 29, 2017 · 6x^2+x-1 = (2x+1) (3x-1) Here are a couple of methods (in no particular order): Method 1 Note that: (ax+1) (bx-1) = abx^2+ (b-a)x-1 Comparing with: 6x^2+x-1 we want to find …

How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs

We're dividing a single term, #6x^3#, into a polynomial, so we can take advantage of the following fact which allows us to effectively divide one term into other terms:

Explanation: From the given #int ( (2x+13)dx)/ (x^2+6x+13) # We can expand the integrand this way #int ( (2x+13)dx)/ (x^2+6x+13)=int ( (2x+6+7)dx)/ (x^2+6x+13) # Then ...

6x-y=11 The equation of a line in color (blue)"point-slope form" is. color (red) (bar (ul (|color (white) (2/2)color (black) (y-y_1=m (x-x_1))color (white) (2/2 ...